(x+1)^2/(x^2-1)

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Solution for (x+1)^2/(x^2-1) equation: 


D( x )

x^2-1 = 0

x^2-1 = 0

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in (-oo:-1) U (-1:1) U (1:+oo)

((x+1)^2)/(x^2-1) = 0

x+1 = 0 // - 1

x = -1

x in { -1} 

x belongs to the empty set

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